-x^2+6x+60=0

Solution for -x^2+6x+60=0 equation:

-x^2+6x+60=0

We add all the numbers together, and all the variables

-1x^2+6x+60=0

a = -1; b = 6; c = +60;
Δ = b2-4ac
Δ = 62-4·(-1)·60
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{69}}{2*-1}=\frac{-6-2\sqrt{69}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{69}}{2*-1}=\frac{-6+2\sqrt{69}}{-2}
$